Anti derivative of sin 2x FASTT Please

1.	Anti derivative of sin 2x FASTT Please
Answer» ANSWER: $\sf{}\because sin2x=\dfrac{d}{dx}\bigg\lgroup-\dfrac{1}{2} cos2x\bigg\rgroup$ Step-by-step explanation: The ANTI DERIVATIVE of sin 2x is a function of X whose derivative is sin 2x. It is known that, $\sf{}\dfrac{d}{dx}(cos2x)=-2sin 2x$ $\sf{}\Rightarrow sin2x=-\dfrac{1}{2}.\dfrac{d}{dx}(cos2x)$ $\sf{}\because sin2x=\dfrac{d}{dx}\bigg\lgroup-\dfrac{1}{2} cos2x\bigg\rgroup$ $\sf{Therefore,\ the\ anti\ derivative\ of\ sin 2}\ is\ -\dfrac{1}{2}cos2x$

Answer»

$\sf{}\because sin2x=\dfrac{d}{dx}\bigg\lgroup-\dfrac{1}{2} cos2x\bigg\rgroup$