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LET The NUMBER Be X

=  >  \frac{4x}{5}  \:  -  \frac{3x}{8} = 68\\  \\  =  >  \frac{32x - 15x}{40}  = 68 \\  \\  =  >  \frac{17x}{40}  = 68 \\  \\   =  > 17x = 2720 \\  \\  =  > x = 160

Hence , The REQUIRED Number Is\fbox{160}

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