Answer the following questions with respect to the compound NO[BF_4] (P)Bond order of the part underlined. (Q)Total number of sigma bonds in the compound. (R)Total number of pi bonds in the compound .

Answer the following questions with respect to the compound NO[BF_4]

1.	Answer the following questions with respect to the compound NO[BF_4] (P)Bond order of the part underlined. (Q)Total number of sigma bonds in the compound. (R)Total number of pi bonds in the compound .
Answer» SOLUTION :`NO^(-)[BF_4]^-` (P)Molecular orbital electronic configuration , `NO^(+)` is derivative of `O_2`, so MOT configuration is : `sigma1s^2 SIGMA^()1s^2sigma2s^2 sigma^()2s^2sigma2p_x^2 pi2p_y^2=pi2p_z^2` ( x is taken as molecular axis) Bond order =`(10-4)/2=3` One `sigma` bond are two `pi` bonds. (Q)NUMBER of `sigma` bonds in `NO^+` is one and in `BF_4^-` are four. So total number of `sigma` bonds are five. (R)Number of `pi` bonds is `NO^+` are two. (S) Steric number of CENTRAL atom boron is 4+0=4, so its hybridisation is `sp^3` and thus the number of hybrid ORBITALS involved in `sp^3` hybridisation is four.