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Answer the following questions pertaining to the brown ring test for nitric acid:1. Name the chemical constituent of the brown ring ‘Y’. 2. Which of the two solutions – iron (II) sulphate or cone, sulphuric acid, do ‘X’ and ‘Z’ represent3. State why the unstable brown ring decomposes completely on disturbing.4. Give a reason why the brown ring does not settle down at the bottom of the test tube.5. Name the gas evolved when acidified iron (II) sulphate reacts with dilute nitric acid in the brown ring test. |
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Answer» (1) FeSO4 .NO (2) X-FeSO4 Z-H2SO4 (3) When test tube is disturbed, cone. H2SO4 mixes with water (in Fe2SO4 solution). Dilution of cone. H2SO4 with water is an exothermic process. The heat so produced assists in the decomposition of unstable brown ring. (4)Cone. H2SO4 ), (density 1.98) is twice as heavy as water (density : 1). As such cone. H2SO4 settles down and iron(II) sulphate layer remains alone it resulting in the formation of brown ring at the junction. (5) Nitric oxide (NO). |
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