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Answer the following questions :1. Find the distance to the point (2, 3) from the origin.2. Show that the points (-1, 7), (3, -5) and (4, -8) are collinear.3.If p(x, y) is equidistant from (2,3) and (-2, -3), then write the relation between x and y.4.Find the perimeter of the triangle whose vertices are (3, 2), (2, -3) and (0,0).5.Show that the points (-1, -8), (4,-6), (2,-1), (-3,-3) taken in order form a square. |
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Answer» Answer: (2,3) origin =(0,0) LET 2 be x1 and 3 be y1 and 0 be x2 and 0 be y2 √(0-2)^2 + (0-3)^2 √(-2)^2 +(-3)^2 √4+9 =√13 3.605 Therefore the answer is 3.605 2. 1/2| x1(y2 - y3) +x2 (y3 - y1) + x3 (y1- y2)| (-1,7) (3,-5) (4,-8) (x1,y1)(x2,y2)(x3,y3) 1/2| -1 (-5 +8) + 3 (-8 -7) + 4 (7 +5)| 1/2| 5-8-24-21+28+20| 1/2| 53 -53 | 1/2| (0) 1/2*0 0/2 =0 Therefore the points are COLLINEAR. |
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