1.

Answer my question no 13.First (right) answer will be brainliest.

Answer»

Given Principal = 46875, R = 8.


(1) Interest for the 1ST year:


We know that A = P(1 + r/100)^n


= > 46875(1 + 8/100)^1


= > 46875(1 + 8/100)


= > 46875(108/100)


= > 46875(27/25)


= > 50625.


We know that CI = A - P


= 50625 - 46875


= 3750.






(ii)


the amount standing to his credit at the end of the second year.


= > A = P(1 + r/100)^n


= 46875(1 + 8/100)^2


= 46875(108/100)^2


= 46875(27/25)^2


= 54675.






(IV) Amount at the end of 3rd year.


= > A = 46875(1 + 8/100)^3


= 46875(108/100)^3


= 46875(27/25)^3


= 59049.



(iii) Interest for the 3rd year:


= > CI = A - P


= 59049 - 54675


= 4374.




Hope this helps!


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