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Answer it I will mark you as brainalist answer |
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Answer» Answer: The given set of points (a,-2),(a,3),(a,0) in each case are COLLINEAR. Step-by-step EXPLANATION: Let the given set of points (a,-2), (a,3) & (a,0) be the vertices of triangle ABC such that Coordinates of A = (x1,y1) = (a, -2) Coordinates of B = (x2,y2) = (a, 3) Coordinates of C = (x3,y3) = (a, 0) We know that three points are collinear if and only if the area of the triangle ABC is zero. So, The formula for the area of ∆ABC is given as, = ½ * [x1(y2-y3) + x2(y3-y1) + x3(y1-y2)] substituting the VALUES, we get = ½ * [a(3-0) + a{0 - (-2)} + a(-2 - 3)] = ½ * [ 3a + 2A - 5a] = ½ * 0 = 0 ∴ Area of ∆ABC = 0 ⇒ Points A, B and C lie on the same line ⇒ A, B and C are collinear points. Thus, the given set of points (a,-2),(a,3) & (a,0) are collinear.
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