Answer it I will mark it as brainliest

1.	Answer it I will mark it as brainliest
Answer» 750 m is the answer Let the SPEED of sound be s And the speed of sound is same for both EVENTS... By which we can say that 2l /t = s Where l is distance between cliff and SOURCE and t is the time of echo... So, the first CASE will be 2l/4 = s And second case will be 2l-150/3.6 = s Equating both equation 2l/4=2l -150/3.6 7.2l = 8L - 600 600 = 0.8l hence l = 750m Hope it helped Pls Mark me as brainliest..

Answer»

750 m is the answer

Let the SPEED of sound be s

And the speed of sound is same for both EVENTS...

By which we can say that

2l /t = s

Where l is distance between cliff and SOURCE and t is the time of echo...

So, the first CASE will be

2l/4 = s

And second case will be

2l-150/3.6 = s

Equating both equation

2l/4=2l -150/3.6

7.2l = 8L - 600

600 = 0.8l

hence l = 750m

Hope it helped

Pls Mark me as brainliest..

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