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Answer» n:10 mL of water required 1.47 mg of K₂Cr₂O₇ (molecular weight =294) for oxidation of DISSOLVED organic matter. C.O.D (Chemical Oxygen Demand) of water is?Answer:According to the question,⇒ 10 mL of water (H₂O) requires 1.47 mg of K₂Cr₂O₇ for oxidationIt can also be written as,⇒ 10 mL of water (H₂O) requires 1.47 X 10⁻³ g of K₂Cr₂O₇∵ 1 milligram (mg) = 10⁻³ gThen,10⁶ mL of water (H₂O) requires 1.47 g of K₂Cr₂O₇So Here,49 g of K₂Cr₂O₇ requires 8 g O₂147 g of K₂Cr₂O₇ requires g of O₂This can be represented as Hence option (B) is correct |
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