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Anhydrous AlCl_3is covalent. From the data given below, predict whether it would remain covalent or become ionic in aqueous solution. (Ionization energy for Al = 5137 kJ "mole"^(-1), Delta H_("hydration")for Al^(3+) = -4665 kJ "mole"^(-1) , Delta H_("hydration") for Cl^(-) = -381 kJ "mole"^(-1)). |
| Answer» Solution : TOTAL ENERGY evolved due to hydration = -4665 - 36-381) = -5808 kJ/mole. As this RELEASED energy is greater than ionization energy (5137 kJ/mole) of AL, `AlCl_3`can be ionic in aqueous solution. | |