1.

Anhydrous `AlCl_(3)` is covalent. From the data given below, predict whether it would remain covalent or become ionic in aqueous solution (Ionization energy for `Al=5137 kJ "mol"^(-1), Delta H_("hydration") "for" Al^(3+) = - 4665 kJ "mol"^(-1), Delta H_("hydration")` for `Cl^(-1)=-381 kJ "mol"^(-1))`.

Answer» Total energy released due to hydration of ions = - 4665`-3xx381=-5808 kJ "mol"^(-1)`. This energy is greater than the ionisation energy of Al which is 5137 kJ `"mol"^(-1)`. Hence , it would be ionic in the solution .


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