1.

Anhydrous AlCl_(3) is covalent. From the data given below : Lattice energy = 5137 kJ/mol DeltaH hydration for Al^(+3) = –4665 kJ/mol DeltaH hydration for Cl^(-) = -381 kJ/mol Correct statement is :-

Answer»

The solution will consist of `AL^(+3) & CL^(-)`
The solution will consist of hydrated `Al^(+3) & Cl^(-)`
It will remain covalent in aqueous solution
None

Solution :`DELTAH`hydration for `Al^(+3)= -4665 K^(-1)`MOL
`DeltaH`hydration for `Cl^(-) = -381` kJ/mol
In `AlCl_(3) to 3Cl^(-)`
so, `DeltaH` hydrationfor `3Cl^(-) = -381 xx 3 = -843`
Total hydration enthalpy
`=-4665+ -843 = -5508`
Lattice energy = 5137
Hydration energy is more than lattice energy


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