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`angleA + 1/2 angleB+ angleC=140^(@)`, then `angleB` is `angleA +1/2angleB + angleC=140^(@)`, हे, तब `angleB` हे।A. `50^(@)`B. `80^(@)`C. `40^(@)`D. `60^(@)` |
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Answer» Correct Answer - B According to question, `angleA + 1/2 angleB+ angleC = 140^(@)`………….(i) As we know that `angleA+angleB+angleC=180^(@)` ……………(iii) Compare equation (i) and (ii) `1/2angleB= 40^(@)` `angleB=90^(@)` |
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