Anexamination is being held in two parts and there are 572 examinees i

1.	Anexamination is being held in two parts and there are 572 examinees in all of the totalnumber of examinees appears in part I only and appears in part II only. The rest appearin both the parts. Find the number of candidates appearing in both the parts.ruad the other
Answer» n(A U B) =n(A) +n(B) -n(A n B) 572=3/11572 +3l13572 -n(A n B) no. of candidates appearing in both the parts=572(1-3/11-3/13) =572(143-39-33) /143=572(143-72) /143=57271/143=471=284

Anexamination is being held in two parts and there are 572 examinees in all of the totalnumber of examinees appears in part I only and appears in part II only. The rest appearin both the parts. Find the number of candidates appearing in both the parts.ruad the other

Answer»

n(A U B) =n(A) +n(B) -n(A n B) 572=3/11*572 +3l13*572 -n(A n B)

no. of candidates appearing in both the parts=572(1-3/11-3/13) =572*(143-39-33) /143=572*(143-72) /143=572*71/143=4*71=284