Andrew is two years older than Beatrice, and Chris is three years youn

1.	Andrew is two years older than Beatrice, and Chris is three years younger than Beatrice.The sum of Andrew's age and Chris' age is 67. Let b represent Beatrice's age.Write an equation that would help determine Beatrice's age.
Answer» ☆ Solutions Let BEA = x Therefore Andrew = x + 2 Chris = x - 3 Andrew Chris = 66 (x + 2)(x-3) = 66 Remove the brackets. x^2 + 2x -3x - 6 = 66 x^2 - x - 6 = 66 SUBTRACT 66 from both sides. x^2 - x - 72 = 0 (x - 9)(x + 8) = 0 Find the possible values of Bea's age X-9=0 x = 9 That value works. She can be plus 9 years old. x + 8 = 0 x = - 8. There's no way she can be - 8 years old So Bea is 9. 》Answer - 9

Andrew is two years older than Beatrice, and Chris is three years younger than Beatrice.The sum of Andrew's age and Chris' age is 67. Let b represent Beatrice's age.Write an equation that would help determine Beatrice's age.

Answer»

☆ Solutions

Let BEA = x

Therefore Andrew = x + 2 Chris = x - 3

Andrew Chris = 66

(x + 2)(x-3) = 66 Remove the brackets.

x^2 + 2x -3x - 6 = 66

x^2 - x - 6 = 66 SUBTRACT 66 from both sides.

x^2 - x - 72 = 0

(x - 9)(x + 8) = 0

Find the possible values of Bea's age

X-9=0

x = 9 That value works. She can be plus 9 years

old.

x + 8 = 0

x = - 8. There's no way she can be - 8 years old

So Bea is 9.

》Answer - 9

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Andrew is two years older than Beatrice, and Chris is three years younger than Beatrice.The sum of Andrew's age and Chris' age is 67. Let b represent Beatrice's age.Write an equation that would help determine Beatrice's age.​