1.

and x+3Y-2-03) Find the joint equation of the lines 3x+2Y-1-0

Answer»

joint equation of line is

L1.L2 = 0

=> (3x+2y-1)(x+3y-2) = 0=> 3x²+9xy-6x+2xy+6y²-4y-x-3y+2 = 0=> 3x²+6y²+11xy-7x-7y+2 = 0



Discussion

No Comment Found