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and x+3Y-2-03) Find the joint equation of the lines 3x+2Y-1-0 |
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Answer» joint equation of line is L1.L2 = 0 => (3x+2y-1)(x+3y-2) = 0=> 3x²+9xy-6x+2xy+6y²-4y-x-3y+2 = 0=> 3x²+6y²+11xy-7x-7y+2 = 0 |
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