1.

And the values of K so that the area of the triangle withvertices [1,-1) {-4, 2k)and (-k,-5) is 24 sq units​

Answer»

Answer:

Area of triangle=1/2|x1(y2-y3)+X2(y3-y1)+X3(y1-y2)|

Here x1=1,x2=-4.x3=-k

y1=-1,y2=2k,y3=-5

SOLUTION:......

1/2|1(2k-(-5)+-4(-5-(-1)+-k(-1-2k)|=24

1/2|2k+5+16+k-2k|=24

1/2|k+21|=24

|k+21|=24×2=48

|k+21|=48

|k|=48-21=27

k=27


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