Saved Bookmarks
| 1. |
and (,-3).9. A point Pis at a distance of v10 from the point (4, 3). Find the co-ordinates of point Pif its ordinate is twice of its abscissa. |
|
Answer» Let the point P is (x, y)Then, y = 2x Given Distance between points= sqrt(10) Thus,sqrt(10) = sqrt((4-x)^2 + (3 - y)^2))Squaring both sides10 = (4-x)^2 + (3 - 2x)^210 = 16 + x^2 - 8x + 9 + 4x^2 - 12x5x^2 - 20x + 15 = 05x^2 - 15x - 5x +15 =05x(x - 3) - 5(x - 3) = 0(5x - 5)(x - 3) = 0x = 1, 3 Coordinates are (1, 2) and (3, 6) |
|