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AnAP consists of 50 terms of which 3rd term is 12 andthe last term is 106. Find the 29th term.19 |
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Answer» nth term = a + (n-1)d where a is first term and d is common difference 3rd term = a + 2d = 12 last term = 50th term = a + 49d = 106 a + 49d - a - 2d = 106 - 12 47d = 94 d = 2 a + 4 = 12 a = 8 29th term = a + 28d = 8 + 28×2 = 8 + 56 = 64 If you find this answer helpful then like it. |
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