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Analysis shows that nickel oxide has the formula Ni_(0.98)O_(1.00). What fractions of nickel exist as Ni^(2+) and Ni^(3+) ions ? |
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Answer» Solution :Let number of O-atoms = 100 `therefore`Number of Ni atoms = 98 Let number of `Ni^(2+) = X` . `therefore` Number of nickel atoms as `Ni_("IONS")^(3+) = (98 - x)` Since compound is neutral we GET ` 3(98 - x) + 2x = 2 xx 100` `therefore 294 + x = 200` `therefore x = 94` Fraction of Ni present as `Ni^(2+) =94/98 xx 100` ` = 95.9 ~~ 96%` `therefore` Fraction of Ni present as `Ni^(3+) = (100 - 96)` = 4% |
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