1.

Analysis shows that nickel oxide has the formula Nio_(0.98)O_(1.00). What fractions of nickel exist as Ni^(2+) and Ni^(3+) ions ?

Answer»

Solution :The formula of the oxide is `Ni_(0.98)O_(1.00)`
LET the number of `O^(2-)` ions be 100.
Then number of nickel ions = 98
Let the number of `Ni^(2+)` be = x
Then number of `Ni^(3+)=98-x`
Total charge on cations = Total charge on anions
`(x)XX(+2)+(98-x)xx(+3)=100xx2`
`"or"2x+294-3x=200 or x = 94`
Percentage of `Ni^(2+)=(94)/(98)xx100=96`
Percentage of `Ni^(3+)=100-96=4.`


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