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Analysis shows that nickel oxide has the formula Ni_(0.96) O. What fractions of the nickel exist as Ni^(2+) and Ni^(3+). |
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Answer» Solution :98 Ni atom are associated with 100 O atom. Out of 98 Ni ATOMS, suppose Ni present as `Ni^(2+) =x` Then Ni present as `Ni^(3+)= 98-x` Then Ni present as `Ni^(3+) = 98-x` Total change on x `Ni^(2+)` and `(98-x) Ni^(3+)` should be equal to total change on `100 O^(2-)` Hence. `2 xx x + 3 xx (98-x) = 100xx 2` Or, `2x + 294-3x = 200` `therefore x = 94` `therefore` Fraction of Ni present as `Ni^(2+) = 94/98 xx 10 = 96%` Fraction of `Ni^(3+)` present as `Ni^(3+) = 4/98 xx 100 = 4%` |
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