1.

Analysis of a gaseous compound C Cl_(x)F_(y), shows that it contains 11.79% C and 69.57% Cl. In another experiment, you find the 0.051 gm of compound fills a 224 ml flask at 0^(@)C wit a pressure of 19 mm Hg. The value of 'x' is :

Answer»


Solution :`PV = nRT`
`(19)/(760) xx (224)/(1000) = (0.051)/(M) xx 0.0821 xx 273`
`M = 204 gm//mol`
`C Cl_(x)F_(y)`
`{:("Element",% "composition","Mole","ATOMS",),(C,11.79,(11.79)/(12)= 0.98,1,),(Cl,69.57,(69.57)/(35.5)= 1.96,2,),(F,18.64,(18.64)/(19) = 0.98,1,):}`
Emperical FORMULA `= CCl_(2)F`
Emperical MASS `= 102`
Molecular mass `= "Emperical mass " xx n`
`204 ""= 102 xx n`
`n = 2`
Molecular formula `= C_(2)Cl_(4)F_(2)`
`x = 4`


Discussion

No Comment Found

Related InterviewSolutions