1.

anA+SecA-1 _1+SinA26. “anA-SecAtl CosA1 1 1

Answer»

(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/cos A

multiply LHS by cosA /cosA to get(sinA+1-cosA) / (sinA-1+cosA)

multiply again by cosA/cosA to get(sinA.cosA+cosA-cos^2A) / cosA(sinA-1+cosA)

= ( cosA(1+sinA) - (1-sin^2A) ) / cosA(sinA-1+cosA)= ( cosA(1+sinA) - (1+sinA)(1-sinA) ) / cosA(sinA-1+cosA)= ( (1+sinA)(cosA-1+sinA) ) / cosA(sinA-1+cosA)= (1+sinA)/cosA

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