An X-ray tube operating at 50kV converts `1%` energy in the form of X-ray. If the amount of heat produced is 495 watt, then the number of electrons colliding with the target per second isA. `6.25xx10^(16)`B. `4.15 xx10^(16)`C. `3.2xx10^(16)`D. `1.2xx10^(16)`

An X-ray tube operating at 50kV converts `1%` energy in the form of X-

1.	An X-ray tube operating at 50kV converts `1%` energy in the form of X-ray. If the amount of heat produced is 495 watt, then the number of electrons colliding with the target per second isA. `6.25xx10^(16)`B. `4.15 xx10^(16)`C. `3.2xx10^(16)`D. `1.2xx10^(16)`
Answer» Correct Answer - A `N=495/(50 KeV) =6.25 xx10^(16)`

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An X-ray tube operating at 50kV converts `1%` energy in the form of X-ray. If the amount of heat produced is 495 watt, then the number of electrons colliding with the target per second isA. `6.25xx10^(16)`B. `4.15 xx10^(16)`C. `3.2xx10^(16)`D. `1.2xx10^(16)`

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