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An X-ray beam (lambda = 70.9 pm) was scattered by a crystalline solid. The angle (2 theta) of the diffraction for a second order reflection is 14.66°. Calculate the distance between parallel planes of atoms of the crystalline solid. |
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Answer» Solution :The Bragg.s equation is given as, n `lambda = 2D sin THETA` `n=` order of reflection `=2` `lambda =2` WAVE length of X-rays `=7.09 xx 10^(-11) `m `theta =` ANGLE of reflection `=7.33^(@)` `d=` DISTANCE between parallel planes Distance between parallel planes `=d= (lambda)/( sin theta) = (7.09 xx 10^(-11) )/ ( sin 7.33^(@) ) = 6.18 xx 10^(-10) m` |
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