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An X-ray beam (lambda = 70.9 p m) was scattered by a crystalline solid. The angle (2theta) of the diffraction for a second order reflection is 14.66^(0). Calculate the distance between parallel planes of atoms of the crystalline solid. |
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Answer» Solution :The Bragg’s equation is given as, `nlambda. = 2d SIN theta` N = order of reflection = 2 `lambda`= wave length of X-rays = `7.09 xx 10^(-11)m` `theta` = ANGLE of reflection = `7.33^(@)` d = distance between PARALLEL planes Distance between parallel planes (d) = `(lambda)/(sin theta)=(7.09xx10^(-11))/(sin 7.33^(@)) d= 6.18 xx10^(-10)m ` |
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