An unknown quantity `'alpha'` is expressed as `alpha = (2ma)/(beta) log(1+(2betal)/(ma))` where m = mass, a = acceleration `l` = length, The unit of `alpha` should beA. meterB. m/sC. `m//s^(2)`D. `s^(-1)`

An unknown quantity `'alpha'` is expressed as `alpha = (2ma)/(beta) lo

1.	An unknown quantity `'alpha'` is expressed as `alpha = (2ma)/(beta) log(1+(2betal)/(ma))` where m = mass, a = acceleration `l` = length, The unit of `alpha` should beA. meterB. m/sC. `m//s^(2)`D. `s^(-1)`
Answer» Correct Answer - A `[(2 beta l)/(ma)] = M^(0)L^(0)T^(0)` `[(beta)/(ma)] = [(1)/(l)]` `[alpha] = [(ma)/(beta)] = [l]`

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An unknown quantity `'alpha'` is expressed as `alpha = (2ma)/(beta) log(1+(2betal)/(ma))` where m = mass, a = acceleration `l` = length, The unit of `alpha` should beA. meterB. m/sC. `m//s^(2)`D. `s^(-1)`

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