1.

an oxide of metal M has 47% by mass of oxygen. Metal M has atomic mass of 24. the empirical formula of the oxide is

Answer»

HEYA MATE,

HERE IS UR ANSWER.

THANKS for asking this question.

The formulae of the oxide is :

M x O y

Let X be MOLES of M and y be moles of OXYGEN.

Mass of oxygen is 0.47g

Mass of M is 0.53g

Moles of M = 0.53 / 24 = 0.02

Moles of Oxygen = 0.47 / 16 = 0.03

Mole ratio :

M : O = 0.02 : 0.03

= 2:3

The empirical formula of the oxide is thus :

M3O4

I HOPE IT HELPS U.


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