1.

An organic compound (X) (mol. Wt= 94) containing C, H and O gave on analysis 76.6% C, 6.38%% H and 17.02%O. A solution of (X) in aqueous NaOH with FeCl_(3) gave a violet colour while when heated with C Cl_(4), it produced an acid (Y) of molecular weight 138. Find (X) and (Y)

Answer»

Solution :Moles of `C: H: O= (76.60)/(12): (6.38)/(1): (17.02)/(16)`
`=6.38: 6.38: 1.05`
`=6:6:1`
Empirical formula of (X) is `C_(6)H_(6)O` (94)
As mol. Wt of (X) is ALSO 94,
molecular formula of (X) is `C_(6)H_(6)O`. Further, since the solution of (X) in aqueous NaOH gives violet colour with `FeCl_(3)`, (X) must contain a phenolic group. Hence (X) is `C_(6)H_(50OH`. From the next given information, i.e., ALKALINE solution of (X) with `C Cl_(4)`, on heating,produces an acid of molecular weight 138, the acid (Y) must be


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