1.

An organic compound undergoes first order decomposition. The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are t_(1/8) and t_(1//10) respectively. What is the value of ([t_(1//8)])/([t_(1//10)])xx10? (log_(10)2=0.3)

Answer»


SOLUTION :`(Kxxt_(1/8))/(Kxxt_(1/10))=(2.303xxltg((C_(0))/(C_(0)//8)))/(2.303xxlog((C_(0))/(C_(0)//10))),((t_(1/2))/(t_(1/10)))=(log_(8))/(log_(10)^(10))=(3xxlog2)/1=3xx0.3010=0.9,((t_(1/8))/(t_(1/10)))=10x0.910=9`


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