1.

An organic compound undergoes first-order decomposition. The time taken for its decomposition to 1//8 and 1//10 of its initial concentration are t_(1//8) and t_(1//10) respectively. What is the value of ([t_(1//8)])/([t_(1//10)])xx10?(log_(10)2=0.3)

Answer»


Solution :For a first order REACTION,
`k=(2*303)/t"log"C_0/C_t" or "t=(2*303)/k"log"C_0/C_t`
`:.""1_(1//8)=(2*303)/t"log"C_0/(C_0//8)=(2*303)/k"log 8"`
`=(2*303)/k"log 2"^3=(2*303xx3)/k"log 2"`
`=(2*303xx3xx0*3)/k`
`t_(1//2)=(2*303)/k"log"C_0/(C_0//10)=(2*303)/k" log 10"=(2*303)/k`
`:.""t_(1//8)/t_(1//10)=3xx0*3=0*9" or "t_(1//8)/(t_(1//10))" or "t_(1//8)/t_(1//10)xx10=9`


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