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| 1. |
An organic compound undergoes first decompoistion. The time taken for its decompoistion to 1//8 and 1//10 of itsinitial concentration are t_(1//8) and t_(1//10), respectively. What is the value of ([t_(1//8)])/([t_(1//10)]) xx 10? (log_(10)2 = 0.3) |
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Answer» 0.6 |
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