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An organic compound contains C=40% , H=13.33% and N=46.67%. Its empirical formula would be

Answer»

`CHN`
`C_(2)H_(2)N`
`CH_(3)N`
`C_(3)H_(2)N`

Solution :As in above question, `C=(40)/(12)=3.33: H=(13.33)/(1)=13.33: N=(46.67)/(14)=3.34`
Relative No. of atoms `C=(3.33)/(3.33)=1, H=(13.33)/(3.33)=4, N=(3.34)/(3.33)=1`
`therefore` Empirical formula`=CH_(4)N`


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