An organic compound contains c = 36% , h=6% what is the emperical form

1.	An organic compound contains c = 36% , h=6% what is the emperical formula
Answer» Answer: CH2 Explanation: Percentage of carbon==>36 Percentage of hydrogen ==>6 Atomic mass of carbon ===>12 gram per mole. Atomic mass of hydrogen ==>1 gram per mole. Now divide the mass percentage by atomic mass of the element. Carbon ==>36/12=3 Hydrogen ==>6/1=6 To calculate EMPIRICAL formula we should calculate the simplest RATIO . *For* *this* *divide* *the* *equation* 1 by *the* *SMALLEST* *RESULT* . Carbon=>3/3=1 Hydrogen ==>6/3=2 The empirical formula is *CH2. Please* *mark* it as *BRAINLIST*.

An organic compound contains c = 36% , h=6% what is the emperical formula

Answer»

Answer:

CH2

Explanation:

Percentage of carbon==>36

Percentage of hydrogen ==>6

Atomic mass of carbon ===>12 gram per mole.

Atomic mass of hydrogen ==>1 gram per mole.

Now divide the mass percentage by atomic mass of the element.

Carbon ==>36/12=3

Hydrogen ==>6/1=6

To calculate EMPIRICAL formula we should calculate the simplest RATIO .

For this divide the equation 1 by the SMALLEST RESULT .

Carbon=>3/3=1

Hydrogen ==>6/3=2

The empirical formula is CH2.

Please mark it as BRAINLIST.