1.

An organic compound containing C,H and Ngavefollowing analysis : C = 40%, H = 13.33% and N = 46.67%. It empirical formula would be

Answer»

`C_(2)H_(7)N_(2)`
`CH_(5)N`
`CH_(4)N`
`C_(2)H_(7)N`

Solution :`{:("ELEMENT"," NO. of MOLES"," SIMPLE ratio"),(C 40%,40//12=3.33,1),(H13.33%,13.33//1=13.33,4),(N46.67%,46.67//14=3.33,1):}`
THUS formula `CH_(4)N`.


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