1.

An organic compound containing C = 38.8%, H = 16% and n = 45.2%. Empirical formula of the compound is

Answer»

`CH_(3)NH_(2)`
`CH_(3)CN`
`C_(2)H_(5)CN`
`CH_(2)(NH)_(2)`

Solution :`{:("Element"," NO. of moles"," Simple RATIO"),(C=38.8,38.8//12=3.2,1),(H=16,16//1=16,5),(N=45.2,45.2//14=3.2,1):}`
THEREFORE, Empirical formula `= CH_(5)N` or `CH_(3)NH_(2)`.


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