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An organic compound (A) with molecular formula C_(3)H_(6)O undergoes iodoform reaction. Two molecules of compound (A) react with dry HCl to give compound (B) (C_(6)H_(10)O). Compound (B) reacts with one more molecule of compound (A) to give compound (C) (C_(9)H_(14)O). Identify (A), (B) and ( C). Explain the reactions. |
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Answer» Solution :(i) Compound (A) with molecular formula `C_(3)H_(6)O` that undergoes IODOFORM reaction is `CH_(3)COCH_(3)` (A) (acetone). (ii) TWO MOLECULES of (A) react with dry HCL to give compound (B). (iii) Compound (B) reacts with (A) to give compound ( C).
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