1.

An organic compound A upon reacting with NH_3 gives B. On heating B gives C. C in presence of KOH reacts with Br_2 to given CH_3CH_2NH_2 . A is :

Answer»

`CH_3COOH`
`CH_3CH_2CH_2COOH`
`CH_3-underset(CH_3)underset(|)CH-COOH`
`CH_3CH_2COOH`

SOLUTION :`Aunderset"(I)"overset(NH_3)to B underset"II"OVERSETDELTATO C underset"KOH, (III)"overset(Br_2)to CH_3CH_2NH_2`
Reaction (III) is a Hoffmann bromamide reaction . Now formation of `CH_3CH_2NH_2` is possible only from a COMPOUND `CH_3CH_2CONH_2-NH_4^(+)(B)` . Thus (A) should be `CH_3CH_2COOH`


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