An organic compound (A) on treatment with CHCl_(3) and KOH gives two compounds B and C. Both B and C give the same product (D) when distilled with zinc dust. Oxidation of D gives E having molecular formula C_(7)H_(6)O. The sodium salt of E on heating with soda-lime gives F which may also be obtained by distilling A with zinc dust. Identify A to F.

An organic compound (A) on treatment with CHCl_(3) and KOH gives two c

1.	An organic compound (A) on treatment with CHCl_(3) and KOH gives two compounds B and C. Both B and C give the same product (D) when distilled with zinc dust. Oxidation of D gives E having molecular formula C_(7)H_(6)O. The sodium salt of E on heating with soda-lime gives F which may also be obtained by distilling A with zinc dust. Identify A to F.
Answer» Solution :(i) Since compound (A) on treatment with `CHCl_(3)` and KOH (i.E., Reimer-Tiemann reaction), gives two products B and C, THEREFORE, A must be phenol and B and C must be o-hydroxybenzaldehyde and p-hydroxybenzaldehyde respectively or vive-versa. (ii) Since both B and C on distillation with Zn dust give the same compound (D), therefore, D must be BENZALDEHYDE. (III) since oxidation of D gives E with M.F. `C_(7)H_(6)O_(2)`, therefore, E must be benzoic acid. (iv) Since sodium salt of E, i.e., benzoic acid upon heating with soda-lime gives compound (F), therefore, The CHEMICAL equations for the above reactions are given below.