An organic compound (A) on analysis was found to contain C = 16.271%, H = 0.677%, andCl = 72.203%. It reducedFethyng'ssolution and on oxidation gave a monocarboxylic acid (B), having C = 14.679%, H = 0.612%, and Cl = 65.137%. On distillation with sda lime. (B) gave a sweet-smellingliquid(C), containng89.12% chlorine . (C) can alos be obtained by heating (A) with alkali. What structural fornuatewould you assign to (A),(B), and (C)? Explain the above reactions:.

An organic compound (A) on analysis was found to contain C = 16.271%,

1.	An organic compound (A) on analysis was found to contain C = 16.271%, H = 0.677%, andCl = 72.203%. It reducedFethyng'ssolution and on oxidation gave a monocarboxylic acid (B), having C = 14.679%, H = 0.612%, and Cl = 65.137%. On distillation with sda lime. (B) gave a sweet-smellingliquid(C), containng89.12% chlorine . (C) can alos be obtained by heating (A) with alkali. What structural fornuatewould you assign to (A),(B), and (C)? Explain the above reactions:.
Answer» SOLUTION : Molecular formula of `(B) = C_(2)HCl_(3)O_(2)` Comnpound `(A0` SHOWS positive Tollens test so it CONTAINS `(-CHO)` group. Sturcture of `(A)=(overset(C_2HOCl_3)(-CHO))/(underline(Cl_3C-CHO))` `(A)` is chlorol. PERCENTAGE of `Cl` in `CHCl_(3)` (molecular mass of `CHCl_(3) = 12 + 2 + 35.5xx3 = 119.5`) `= (106.5)/(119.5) xx 100 = 89.12%`