An organic compound (A) of molecular formula CH_4O on mild oxidation gives (B) of formula CH_2Othat reduces tollen's reagent. (B) on reaction with methyl magnesium bromide followed by acid hydrolysis will give (C) of molecular formula C_2H_6O which liberates H_2gas with metallic sodium. Identify A, B, C and explain the reactions involved.

An organic compound (A) of molecular formula CH_4O on mild oxidation g

1.	An organic compound (A) of molecular formula CH_4O on mild oxidation gives (B) of formula CH_2Othat reduces tollen's reagent. (B) on reaction with methyl magnesium bromide followed by acid hydrolysis will give (C) of molecular formula C_2H_6O which liberates H_2gas with metallic sodium. Identify A, B, C and explain the reactions involved.
Answer» Solution :(i) (A) is identified from the molecular formula as methanol `(CH_3OH)`. (II) `CH_3OH`- methanol on mild oxidation will give formaldehyde as (B). Aldehydes REDUCE Tollen.s REAGENT to silver mirror. So, (B) is HCHO (METHANAL) `underset("Methanol(A)")(CH_3OH) overset((O))to underset("Methanol(B)")(HCHO)` Formaldehyde REACTS with `CH_3MgBr`. followed by acid hydrolysis produces primary alcohol and (C) is identified from the formula as `CH_3 - CH_2OH` -Ethanol. Ethanol liberates `H_2` gas with metallic sodium.