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An organic compound A of molecular formula C_(3)H_(6)O on reduction with LiAlH_(4) gives B. Compound B gives blue colourin Victor Meyer's test and also forms a chloride C with SOCl_(2). The chloride on treatment with alcoholic KOH gives D. Identify A,B,C and D and explain the reactions. |
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Answer» Solution :(i) Compound (A) is carbonyl compound, it is acetone. (ii) (A) on REDUCTION with`LiAlH_(4)` gives B it gives blue color in Victor Meyer's test. `underset(A)underset(O)underset(||)C-CH_(3) overset(LiAlH_(4))underset([H]) to underset(B)underset(OH)underset(|)(CH_(3)-CH-CH_(2))` (III) (B) REACTS with `SOCl_(2)` to give C. (iii) B reacts with `SOCl_(2)` to give( C). `underset((B))underset(OH)underset(|)(CH_(3)-CH-CH_(2)) overset(SOCl_(2)) to underset(( C))underset(Cl)underset(|)(CH_(3)-CH-CH_(3)) + SO_(2) darr + HCl` (iv) ( C) on treatment with alcoholic KOH, FORMS ( D) by elimination reaction. `underset((C))underset(Cl)underset(|)(CH_(3)-CH-CH_(3)) overset("alc KOH") to underset((D))(CH_(3)CH=CH_(2)+HCl` 
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