An organic compound (A) of molecular formula C_2H_6Oreacts with metallic Na and liberates H_2 gas. (A) on mild oxidation with Cu at 573 K gives (B) of molecular formula C_2H_4O. (B) on reaction with methyl magnesium bromide followed by acid hydrolysis gives (C) of molecular formula C_3H_8O,(C) gives Blue colour in Victor Meyer's test. (C) on mild oxidation with Cu at 573 K gives (D) of formula C_3H_6O. Identify A, B, C, D and explain the reactions.

An organic compound (A) of molecular formula C_2H_6Oreacts with metall

1.	An organic compound (A) of molecular formula C_2H_6Oreacts with metallic Na and liberates H_2 gas. (A) on mild oxidation with Cu at 573 K gives (B) of molecular formula C_2H_4O. (B) on reaction with methyl magnesium bromide followed by acid hydrolysis gives (C) of molecular formula C_3H_8O,(C) gives Blue colour in Victor Meyer's test. (C) on mild oxidation with Cu at 573 K gives (D) of formula C_3H_6O. Identify A, B, C, D and explain the reactions.
Answer» Solution :(i) An organic compound (A) REACTS with Na metal and liberates `H_2` gas means it must be ALCOHOL. From the molecular formula it is identified as Ethanol `(CH_3-CH_2OH)`. (II) Ethanol on oxidation with Cu at 573 K undergoes catalytic dehydrogenation and produes Acetaldehyde as product (B). `underset("Ethanol(A)")(CH_3-CH_2OH) overset(Cu // 573K)to underset("ETHANAL(B)")(CH_3CHO) + H_2uarr` (iii) Acetaldehyde on reaction with `CH_3MgBr` followed by hydrolysis will give Isopropyl alcohol as (C ). (iv) Propan-2-ol is secondary alcohol and so it gives blue colour in Victor Meyer.s test. (C) on reaction with Cu at 573 K will give Propanone as (D). `underset("Propan-2-ol")(CH_3 - underset(OH)underset(\|)(CH)-CH_3)overset(Cu//573K)tounderset("Propanone(D)")(CH_3-underset(O)underset(\|\|)C-CH_3) + H_2uarr`