1.

An organic compound (A) of molecular formula C_2H_6Oon reaction with acidified K_2Cr_2O_7gives (B) of molecular formula C_2H_4Owhich on further oxidation gives (C) of molecular formula C_2H_4O. Compound (C) reacts with (A) in the presence of conc. H_2SO_4gives (D) of molecular formula C_4H_8O_2 .Identify A,B,C,D and explain the reaction involved.

Answer»

Solution :(i) An organic compound (A) of molecular formula `C_2H_6O`is identified as ethanol.
(ii) Ethanol on OXIDATION with acidified` K_2Cr_2O_7`gives first acetaldehyde as (B) which on further oxidation gives acetic acid as (C)
`UNDERSET("ethanol (A)")(CH_3CH_2OH underset(H_2SO_4)overset(K_2Cr_2O_7)(to) underset("acetaldehyde (B) ")(CH_3 - CHO) overset((O))(to) underset("acetic acid (C )")(CH_3COOH)`
(III) Ethanol reacts with acetic acid in the presence of conc. `H_2SO_4` , esterification take PLACE to give ethyl acetate as product (D)
`CH_3-CH_2OH + CH_3COOH overset(conc.H_2SO_4)(to) underset("ethyl ecetate (D)")(CH_3COOC_2H_5 + H_2O)`


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