An organic compound (A) of molecular formula C_2H_4O_2 reacts with PCI_5 to give (B) of formula C_2H_3OCI . (B) on treatment with ammonia gives (C) of formula C_2H_5NO . (C) on reaction with Br_2 and KOH gives CH_5 Nas (D). Identify A,B,C,D and explain the reactions involved.

An organic compound (A) of molecular formula C_2H_4O_2 reacts with PCI

1.	An organic compound (A) of molecular formula C_2H_4O_2 reacts with PCI_5 to give (B) of formula C_2H_3OCI . (B) on treatment with ammonia gives (C) of formula C_2H_5NO . (C) on reaction with Br_2 and KOH gives CH_5 Nas (D). Identify A,B,C,D and explain the reactions involved.
Answer» SOLUTION :(i) The ORGANIC compound (A) is identified as `CH_3 COOH ` (ACETIC acid). (ii) Acetic acid reacts with `PCl_5`to form acetyl CHLORIDE as (B) `HC_3COOH + PCl_5 to underset("acetyl chloride (B)")(CH_3COCl ) + POCl_3 + HCl` (iii) Acetyl chloride on reaction with ammonia gives acetamide as (C) `CH_3COCl + NH_3 to underset("acetamide (C )")(CH_3CONH_2) + HCl` (iv)Acetamide on treatment with `Br_2` and KOH gives methylamine as (D) `CH_3CONH_2 + Br_2 + 4KOH overset(Delta)(to) underset("methyl amine (D) ")(CH_3NH_2) + K_2CO_3 + 2KBr + H_2O`