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An organic compound (A) of molecular formula C_2H_3OCI on reaction with pd and BaSO_4gives (B) of formula C_2H_4O . (B) on reaction with LiAIH_4gives (C) of formula C_2H_6O . (B) on reaction with I_2and NaOH gives (D) of formula CH_2ONa and iodoform. Identify A,B,C,D and explain the reactions involved. |
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Answer» Solution :(i) From the molecular formula (A) is identified as `CH_3COCI`(Acetyl chloride) (ii) Acetyl chloride on treatment with PD and `BaSO_4`gives ACETALDEHYDE `CH_3 CHO`as (B) `underset("acetyl chloride (A)")(CH_3COCl) underset(2[H])overset(Pd//BaSO_4)(to) underset("acetaldehyde (B)")(CH_3CHO) + HCl` (iii) Acetaldehyde on reaction with `LiAlH_4`gives ethyl ALCOHOL as (C) `CH_3CHO underset([H])overset(LiAlH_4)(to) underset("ethyl alcohol (C )")(CH_3 - CH_2 OH)` (IV) Acetaldehyde when treated with `I_2` and NaOH gives sodium formate (D) and iodoform `CHI_3` as products. `CH_3CHO underset(NaOH)overset(3I_2)(to) underset("iodoform")(CHI_3) + underset("sodium formate (D)")` |
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