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An organic compound (A) molecular formula CH_(2)O reacts with CH_(3)MgI to give compound (B). Compound (B) liberates Hydrogen with metallic sodium. Compound (B) in the presence of Conc. H_(2)SO_(4) at 410 K on dehydration to give compound (C ) molecular formula C_(4)H_(10)O. Identify (A), (B) and (C ). Explain the above reactions. |
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Answer» Solution :(i) An ORGANIC compound (A) with molecular formula `CH_(2)O` is formaldehyde (HCHO). `HCHO + CH_(3)MgI overset(H-OH) to CH_(3)CH_(2)OH ` +  (III) ETHANOL on dehydration with conc. `H_(2)SO_(4)`at 410 K gives compound C. `2C_(2)H_(5)OH overset(410 K) underset(H_(2)SO_(4)) to C_(2)H_(5)-O-C_(2)H_(5)` 
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