An organic compound A (molecular formula C2H402) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C3H602). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D. Lakhmir Singh Chemistry Class 10

An organic compound A (molecular formula C2H402) reacts with Na metal

1.	An organic compound A (molecular formula C2H402) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C3H602). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D. Lakhmir Singh Chemistry Class 10
Answer» The COMPOUND A is ethanoic acid which has a structural formula CH3COOH. It gives a pop sound when reacts with sodium because hydrogen GAS is evolved. Compound B is sodium ethanoate, which has a structural formula of CH3COONa. It is formed by the reaction of ethanoic acid with sodium.Methanol, an alcohol is the compound C, which when treated with ethanoic acid forms a compound D in the PRESENCE of concentrated H2SO4.Compound D is an ester which smells sweet. It is methyl ethanoate with the structural formula of CH3COOCH3. CH3OH + CH3COOH ->CH3COOCH3 +H20Methanol and sodium ethanoate is gained back, when methyl ethanoate reacts with sodium hydroxide.CH3COOCH3+ NaOH-> CH3OH+ CH3COONa