1.

An organic compound 'A' having molecular formula C_(2)H_(6)O evolves hydrogen gas on treatment with sodium metal and on treatment with red phosphorous and iodine gives compound 'B'. The compound 'B' on treatment with alcoholic KCN and on subsequent reduction gives compound 'C'. Write the balanced chemical equations for all the reactions involved and identify the compounds 'A', 'B' and 'C'.

Answer»

Solution :`A=C_(2)H_(5)OH"ETHANOL"`
`B=C_(2)H_(5)I"ethyl iodide"`
`C=C_(2)H_(5)CH_(2)NH_(2)" n-propyl amine"`
`underset(A)(2C_(2)H_(5)OH+Na) to underset("Sodium ethoxide")(2C_(2)H_(5)ONa+H_(2))`
`3C_(2)H_(5)OH+PI_(3) underset("in situ")OVERSET(2P+3I_(2))to underset(B)underset("Ethyl iodide")(3C_(2)H_(5)I+H_(3)PO_(3))`
`underset(B)(C_(2)H_(5)I+KCN) underset(Delta)overset("alcohol")to underset("Ethyl NITRITE")(C_(2)H_(5)CN+4(H)) overset(Na//C_(2)H_(5)OH)to underset((C))underset("n-Propyl amine")(C_(2)H_(5)CH_(2)NH_(2))`


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